C-1)
(a³+b³)/(a+b)²-3ab
=(a+b).(a²-ab+b²)/(a²-ab+b²)
=a+b
C-2)
(60)²+(50)²-(58)²-(52)²
=(60)²-(52)²+(50)²-(58)²
=(60-52).(60+52)+(50-58).(50+58)
=8.(60+52)-8.(50+58)
=8(60+52-50-58)
=8.(4)=32
C-3)
a=b-1
=>(1-√a).(1+√a)/(a²-1)
=(1-a)((a-1).(a+1)
=-1/(a+1)
a+1=b
=> -1/b bulunur.
teşekkür ederim
