[Laume]

1) ∫cos(x²-3x).(2x-3).dx=?


2) ∫(x²-2x+3)³(2x-2).dx=?

[Melek12]

C.1
x²-3x=u olsun
du=(2x-3).dx
∫cosu.du=sinu+c=sin(x²-3x)+c

C.2
x²-2x+3=u olsun
du=(2x-2).dx
∫u³.du=u⁴/4 +c=(x²-2x+3)⁴/4+c