saktas133 02:06 13 Şub 2014 #1
(z/(x+y))+(y/(x+z))+(x/(y+z))=1/2
(1/(x+y))+(1/(x+z))+(1/(y+z))=1/12
old. göre x+y+z kaçtır?
şıklar:12,24,36,42,48
ebucihat 02:56 13 Şub 2014 #2
(z/(x+y))+(y/(x+z))+(x/(y+z))=1/2
(1/(x+y))+(1/(x+z))+(1/(y+z))=1/12 x+y+z kaçtır?
(z/(x+y))+(y/(x+z))+(x/(y+z))=1/2 denkleme x+y/x+y x+z/x+z ve y+z/z+y
eklenirse
[(x+y+z)/x+y]+[x(x+y+z)/x+z]+[(x+y+z)/y+z]=1/2+3
(x+y+z+)[1/(x+y))+(1/(x+z))+(1/(y+z)]=7/2
(x+y+z+).1/12=7/2 ise x+y+z=42 bulunur...