Burak Çelebi 16:05 20 Oca 2015 #1
a³-3ab²=10
b³-3a²b=5
a²+b²=?
b³-3a²b=5
a²+b²=?
Süleyman Oymak 02:09 21 Oca 2015 #2
a³-3ab²=10
b³-3a²b=5
(a³-3ab²)²+(b³-3a²b)²=(10)²+(5)²
(a6-6a⁴b²+9a²b⁴)+(b6-6a²b⁴+9a⁴b²)=100+25
a6+3a⁴b²+3a²b⁴+b6=125
(a²+b²)³=5³
a²+b²=5
b³-3a²b=5
(a³-3ab²)²+(b³-3a²b)²=(10)²+(5)²
(a6-6a⁴b²+9a²b⁴)+(b6-6a²b⁴+9a⁴b²)=100+25
a6+3a⁴b²+3a²b⁴+b6=125
(a²+b²)³=5³
a²+b²=5