trigonometri sorusu

pperseus 19:03 15 Haz 2011 #1

√3sin20+cos20/cos40 ?

duygu95 19:25 15 Haz 2011 #2

=> 2[√3/2.sin20+cos20.1/2]/cos40

=2[cos30.sin20+cos20.sin30/cos40]

=2sin50/cos40

=2

pperseus 19:27 15 Haz 2011 #3

sağol

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