[C-1]
(2+i+2-i/2+i-2+i)⁴
=(4/2i)⁴
=(2/i)⁴
=16
[C-2]
2(x+yi)-6i=x-yi
2x+2yi-6i=x-yi
2x+i.(2y-6)=x-yi
x=0, 2y-6=-y ise y=2
x+y=2
(2+i+2-i/2+i-2+i)⁴
=(4/2i)⁴
=(2/i)⁴
=16
[C-2]
2(x+yi)-6i=x-yi
2x+2yi-6i=x-yi
2x+i.(2y-6)=x-yi
x=0, 2y-6=-y ise y=2
x+y=2
teşekkürler