Trigonometri Sorusu

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cevap cotb-cota

sin(a-b)=sina.cosb-cosa.sinb

(sina.cosb-cosa.sinb)/sina.cosb=
(sina.cosb)/(sina.sinb)-(cosa.sinb)/(sina.sinb)=?(mesela (2+4)/2=(2/2)+(4/2))

(cosb/sinb)-(cos/sina)=(cotb-cota).