Sosyal_Bilimci 16:20 31 Mar 2012 #1
(22+ 1) . (24+ 1) . (28+1)= k
(3k+1)1/64 =?
(3k+1)1/64 =?
(2^2-1).(2^2+1).(2^4+1).(2^8+1)/(2^2-1)=k
(2^4-1).(2^4+1).(2^8+1)=3k
(2^8-1).(2^8+1)=3k
(2^16-1)=3k
(3k+1)^(1/64)=(2^16-1+1)^(1/64)=(2^16)^(1/64)=(2^1/4)
(2^4-1).(2^4+1).(2^8+1)=3k
(2^8-1).(2^8+1)=3k
(2^16-1)=3k
(3k+1)^(1/64)=(2^16-1+1)^(1/64)=(2^16)^(1/64)=(2^1/4)