ege.gurtan 12:36 05 Oca 2014 #1
f : [0, pi] ---> [-1, pi ] f (×) = cosx
f in tersi nin türevi (1/2) =? Cvp -2/kök 3
f in tersi nin türevi (1/2) =? Cvp -2/kök 3
yektasimsek 14:49 05 Oca 2014 #2
f(x)=cosx
(f-1)'(1/2)=?
(f-1)(cosx)=x
[(f-1)(cosx)]'=(x)'
-sinx.(f-1)'(cosx)=1
cosx=1/2
x=∏/3
-sin∏/3.(f-1)'(1/2)=1
(f-1)'(1/2)=-2/√3
(f-1)'(1/2)=?
(f-1)(cosx)=x
[(f-1)(cosx)]'=(x)'
-sinx.(f-1)'(cosx)=1
cosx=1/2
x=∏/3
-sin∏/3.(f-1)'(1/2)=1
(f-1)'(1/2)=-2/√3