∫f n(x).f ' (x)dx integralinin eşiti ?
xGrandMasterx 10:54 02 Sep 2013 #2
f(x)= u
f ' (x)dx=du
fn(x)=un
∫fn(x).f ' (x)dx
∫un.du=un+1/n+1=f(x)n+1/n+1
f ' (x)dx=du
fn(x)=un
∫fn(x).f ' (x)dx
∫un.du=un+1/n+1=f(x)n+1/n+1
saol....