1) y=x√a²x²+a²arcsin x/a => y' = ?
2) f(x)=(x-1/2)arcsin√x+1/2√x-x² => f' (1)= ?
3) y=arctane^x -arccote^-x => y'=?
2) f(x)=(x-1/2)arcsin√x+1/2√x-x² => f' (1)= ?
3) y=arctane^x -arccote^-x => y'=?
Süleyman Oymak 00:48 06 Ara 2012 #2 
çok teşekkür ederim