x-y=2 ve xy+z2+2z+2=0 ise x+y+z kaçtır?
x=y+2
(y+2).y+(z+1)²+1
y²+2y+1+(z+1)²=0
(y+1)²+(z+1)²=0
y=-1,z=-1,x=1
x+y+z=-1
(y+2).y+(z+1)²+1
y²+2y+1+(z+1)²=0
(y+1)²+(z+1)²=0
y=-1,z=-1,x=1
x+y+z=-1
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