filozof123 00:11 12 May 2012 #1
sin95.sin55−cos40/2=?
sinavkizi 00:22 12 May 2012 #2
(sin95.sin55−cos40)/2 mi
sin95.sin55−(cos40)/2 mi?
Ceday 00:22 12 May 2012 #3
sinx . siny = -1/2[ cos(x+y) + cos(x-y) ]
sin95.sin55 = -1/2[ cos150 + cos40]
-cos150/2 + cos40/2 - cos40/2
-cos150/2
cos30/2
√3/4