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12 numaralı
b+5a=3a+3b
2b=3a
b=3k, a=2k

sayılar tabandan küçük olmak zorunda, a ve b <5
Bu durumda k=1 için
a=2
b=3

13 numaralı
benden istediği f(g⁻¹(1))=?
sağa ters olarak atarsam:
f⁻¹(x+1)=g⁻¹((x+2)/(2x-1)), g⁻¹'te x=3 verirsem g⁻1'i bulurum.
f⁻¹(4)=g⁻(1)

f(f⁻¹(4))=a olsun
f⁻¹(a)=f⁻¹(4)
demek ki a=4.

1)
https://img62.imageshack.us/img62/2825/mat17072012.png

4)
https://img716.imageshack.us/img716/...at17072012.png

5)
https://img18.imageshack.us/img18/2825/mat17072012.png