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''LOGAR-itma''(5 soru)
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c2
lnx-lny=2
ln(x/y)=2
x/y=e²...
logx-logy=log(x/y)=loge²=2.loge
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https://img811.imageshack.us/img811/...at03112011.jpg
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C-2)
logex-logey=2 verilmiş
e²=x/y bulunur.
logx-logy=log(x/y) olduğundan loge²=2loge bulunur.
C-4)
ln(x-2)-ln(x+2)=1
loge(x-2)/x+2)=1
e=(x-2)/(x+2)
x=(-2-2e)/(e-1) bulunur.
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https://img252.imageshack.us/img252/...t03112011a.gif
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https://img543.imageshack.us/img543/...at03112011.gif
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https://img513.imageshack.us/img513/...at03112011.gif
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ayhaneva, duygu95, LoDoS emeğiniz için teşekkürler.