trigonometri I

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C-1
A+B+C=180 olur.
sin[(A+B)/2]=sin[(180-C)/2]=sin[90-C/2]=cos(C/2) olur.
Çünkü m+n=90 ise sin(n)=cos(m)'dir.
sin[(A+B)/2]-cos[C/2]=cos[C/2]-cos[C/2]=0 olur.

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teşekkürler:)

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teşekkürler :)